A Ball Thrown Straigjt Upward. If It Takes 4.25 Seconds To Reach The Top Of Its Path, What Is Its Initial Speed?

a ball thrown straigjt upward. If it takes 4.25 seconds to reach the top of its path, what is its initial speed?

Good Day

Problem:

a ball thrown straigjt upward. If it takes 4.25 seconds to reach the top of its path, what is its initial speed?

Given Data:

Vi (initial velocity) = ? unknown

Vf (final velocity) = 0 m/s (at top)

t (time)  =  4.25 s

a (acceleration) = -9.8 m/s² (going up decelerating)

Solution:

We can solve the problem using the formula a = (Vf-Vi)/t

To solve for Vi, we can use - Vi = at Vf

- Vi = at Vf

- Vi = -9.8 m/s² × 4.25 s + 0 m/s

- Vi = - 41.65 m/s + 0 m/s

( - Vi = - 41.65 m/s) × -1

  Vi = 41.65 m/s

Hope it helps....=)

Initial Velocity is 41.65 m/s


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