A Ball Thrown Straigjt Upward. If It Takes 4.25 Seconds To Reach The Top Of Its Path, What Is Its Initial Speed?
a ball thrown straigjt upward. If it takes 4.25 seconds to reach the top of its path, what is its initial speed?
Good Day
Problem:
a ball thrown straigjt upward. If it takes 4.25 seconds to reach the top of its path, what is its initial speed?
Given Data:
Vi (initial velocity) = ? unknown
Vf (final velocity) = 0 m/s (at top)
t (time) = 4.25 s
a (acceleration) = -9.8 m/s² (going up decelerating)
Solution:
We can solve the problem using the formula a = (Vf-Vi)/t
To solve for Vi, we can use - Vi = at Vf
- Vi = at Vf
- Vi = -9.8 m/s² × 4.25 s + 0 m/s
- Vi = - 41.65 m/s + 0 m/s
( - Vi = - 41.65 m/s) × -1
Vi = 41.65 m/s
Hope it helps....=)
Initial Velocity is 41.65 m/s
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